(x-4)*(x^2-2x-3)=0

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Solution for (x-4)*(x^2-2x-3)=0 equation: 


Simplifying
(x + -4)(x2 + -2x + -3) = 0

Reorder the terms:
(-4 + x)(x2 + -2x + -3) = 0

Reorder the terms:
(-4 + x)(-3 + -2x + x2) = 0

Multiply (-4 + x) * (-3 + -2x + x2)
(-4(-3 + -2x + x2) + x(-3 + -2x + x2)) = 0
((-3 * -4 + -2x * -4 + x2 * -4) + x(-3 + -2x + x2)) = 0
((12 + 8x + -4x2) + x(-3 + -2x + x2)) = 0
(12 + 8x + -4x2 + (-3 * x + -2x * x + x2 * x)) = 0
(12 + 8x + -4x2 + (-3x + -2x2 + x3)) = 0

Reorder the terms:
(12 + 8x + -3x + -4x2 + -2x2 + x3) = 0

Combine like terms: 8x + -3x = 5x
(12 + 5x + -4x2 + -2x2 + x3) = 0

Combine like terms: -4x2 + -2x2 = -6x2
(12 + 5x + -6x2 + x3) = 0

Solving
12 + 5x + -6x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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